Base | Representation |
---|---|
bin | 110110110100100000111101… |
… | …001110110000110100100111 |
3 | 1011121200020210022121211000001 |
4 | 312310200331032300310213 |
5 | 223100214040210032143 |
6 | 2212441155430202131 |
7 | 101533065550535002 |
oct | 6664407516606447 |
9 | 1147606708554001 |
10 | 241103311408423 |
11 | 6a906381815592 |
12 | 2305b52b1b3347 |
13 | a46bc386a9879 |
14 | 43776692b2539 |
15 | 1cd19b531514d |
hex | db483d3b0d27 |
241103311408423 has 2 divisors, whose sum is σ = 241103311408424. Its totient is φ = 241103311408422.
The previous prime is 241103311408391. The next prime is 241103311408439. The reversal of 241103311408423 is 324804113301142.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 241103311408423 - 25 = 241103311408391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241103311408483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120551655704211 + 120551655704212.
It is an arithmetic number, because the mean of its divisors is an integer number (120551655704212).
Almost surely, 2241103311408423 is an apocalyptic number.
241103311408423 is a deficient number, since it is larger than the sum of its proper divisors (1).
241103311408423 is an equidigital number, since it uses as much as digits as its factorization.
241103311408423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 37.
Adding to 241103311408423 its reverse (324804113301142), we get a palindrome (565907424709565).
The spelling of 241103311408423 in words is "two hundred forty-one trillion, one hundred three billion, three hundred eleven million, four hundred eight thousand, four hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •