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2411124555613 is a prime number
BaseRepresentation
bin100011000101100010001…
…110001111111101011101
322112111112102020012101011
4203011202032033331131
5304000440341234423
65043353315015221
7336124625365564
oct43054216177535
98474472205334
102411124555613
1184a608a544a4
1232b36089a511
131464a285a6a7
14849b02a6bdb
1542abb36ab0d
hex2316238ff5d

2411124555613 has 2 divisors, whose sum is σ = 2411124555614. Its totient is φ = 2411124555612.

The previous prime is 2411124555559. The next prime is 2411124555617. The reversal of 2411124555613 is 3165554211142.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2159494908484 + 251629647129 = 1469522^2 + 501627^2 .

It is a cyclic number.

It is not a de Polignac number, because 2411124555613 - 213 = 2411124547421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2411124555617) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1205562277806 + 1205562277807.

It is an arithmetic number, because the mean of its divisors is an integer number (1205562277807).

Almost surely, 22411124555613 is an apocalyptic number.

It is an amenable number.

2411124555613 is a deficient number, since it is larger than the sum of its proper divisors (1).

2411124555613 is an equidigital number, since it uses as much as digits as its factorization.

2411124555613 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144000, while the sum is 40.

Adding to 2411124555613 its reverse (3165554211142), we get a palindrome (5576678766755).

The spelling of 2411124555613 in words is "two trillion, four hundred eleven billion, one hundred twenty-four million, five hundred fifty-five thousand, six hundred thirteen".