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2411412130013 is a prime number
BaseRepresentation
bin100011000101110011010…
…111010000100011011101
322112112021110100111021212
4203011303113100203131
5304002033001130023
65043442030434205
7336135016624115
oct43056327204335
98475243314255
102411412130013
1184a746311397
1232b421062965
1314651a2c7863
14849da564045
1542ad6722e78
hex231735d08dd

2411412130013 has 2 divisors, whose sum is σ = 2411412130014. Its totient is φ = 2411412130012.

The previous prime is 2411412130009. The next prime is 2411412130037. The reversal of 2411412130013 is 3100312141142.

2411412130013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1281702487129 + 1129709642884 = 1132123^2 + 1062878^2 .

It is a cyclic number.

It is not a de Polignac number, because 2411412130013 - 22 = 2411412130009 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2411412130003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1205706065006 + 1205706065007.

It is an arithmetic number, because the mean of its divisors is an integer number (1205706065007).

Almost surely, 22411412130013 is an apocalyptic number.

It is an amenable number.

2411412130013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2411412130013 is an equidigital number, since it uses as much as digits as its factorization.

2411412130013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 2411412130013 its reverse (3100312141142), we get a palindrome (5511724271155).

The spelling of 2411412130013 in words is "two trillion, four hundred eleven billion, four hundred twelve million, one hundred thirty thousand, thirteen".