Base | Representation |
---|---|
bin | 10110011101110010… |
… | …001011001011111101 |
3 | 2022021002211012021011 |
4 | 112131302023023331 |
5 | 343400213344123 |
6 | 15025334235221 |
7 | 1512523502542 |
oct | 263562131375 |
9 | 68232735234 |
10 | 24122012413 |
11 | a259279a54 |
12 | 48124b5b11 |
13 | 2375679235 |
14 | 124b91abc9 |
15 | 962a92e0d |
hex | 59dc8b2fd |
24122012413 has 2 divisors, whose sum is σ = 24122012414. Its totient is φ = 24122012412.
The previous prime is 24122012389. The next prime is 24122012417. The reversal of 24122012413 is 31421022142.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13196954884 + 10925057529 = 114878^2 + 104523^2 .
It is a cyclic number.
It is not a de Polignac number, because 24122012413 - 217 = 24121881341 is a prime.
It is a super-3 number, since 3×241220124133 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (24122012417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12061006206 + 12061006207.
It is an arithmetic number, because the mean of its divisors is an integer number (12061006207).
Almost surely, 224122012413 is an apocalyptic number.
It is an amenable number.
24122012413 is a deficient number, since it is larger than the sum of its proper divisors (1).
24122012413 is an equidigital number, since it uses as much as digits as its factorization.
24122012413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 24122012413 its reverse (31421022142), we get a palindrome (55543034555).
The spelling of 24122012413 in words is "twenty-four billion, one hundred twenty-two million, twelve thousand, four hundred thirteen".
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