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241221314325451 is a prime number
BaseRepresentation
bin110110110110001110110110…
…110000001010101111001011
31011122002112101010221002200111
4312312032312300022233023
5223104132222431403301
62213011313022215151
7101544444020015035
oct6666166660125713
91148075333832614
10241221314325451
116a951426345709
122307a3821244b7
13a47a0c2bcb525
14437d2612bcc55
151cd4abecd2551
hexdb63b6c0abcb

241221314325451 has 2 divisors, whose sum is σ = 241221314325452. Its totient is φ = 241221314325450.

The previous prime is 241221314325413. The next prime is 241221314325469. The reversal of 241221314325451 is 154523413122142.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 241221314325451 - 215 = 241221314292683 is a prime.

It is a super-2 number, since 2×2412213143254512 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (241221314325401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120610657162725 + 120610657162726.

It is an arithmetic number, because the mean of its divisors is an integer number (120610657162726).

Almost surely, 2241221314325451 is an apocalyptic number.

241221314325451 is a deficient number, since it is larger than the sum of its proper divisors (1).

241221314325451 is an equidigital number, since it uses as much as digits as its factorization.

241221314325451 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 230400, while the sum is 40.

Adding to 241221314325451 its reverse (154523413122142), we get a palindrome (395744727447593).

The spelling of 241221314325451 in words is "two hundred forty-one trillion, two hundred twenty-one billion, three hundred fourteen million, three hundred twenty-five thousand, four hundred fifty-one".