Base | Representation |
---|---|
bin | 110110110110001110110110… |
… | …110000001010101111001011 |
3 | 1011122002112101010221002200111 |
4 | 312312032312300022233023 |
5 | 223104132222431403301 |
6 | 2213011313022215151 |
7 | 101544444020015035 |
oct | 6666166660125713 |
9 | 1148075333832614 |
10 | 241221314325451 |
11 | 6a951426345709 |
12 | 2307a3821244b7 |
13 | a47a0c2bcb525 |
14 | 437d2612bcc55 |
15 | 1cd4abecd2551 |
hex | db63b6c0abcb |
241221314325451 has 2 divisors, whose sum is σ = 241221314325452. Its totient is φ = 241221314325450.
The previous prime is 241221314325413. The next prime is 241221314325469. The reversal of 241221314325451 is 154523413122142.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 241221314325451 - 215 = 241221314292683 is a prime.
It is a super-2 number, since 2×2412213143254512 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (241221314325401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120610657162725 + 120610657162726.
It is an arithmetic number, because the mean of its divisors is an integer number (120610657162726).
Almost surely, 2241221314325451 is an apocalyptic number.
241221314325451 is a deficient number, since it is larger than the sum of its proper divisors (1).
241221314325451 is an equidigital number, since it uses as much as digits as its factorization.
241221314325451 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 230400, while the sum is 40.
Adding to 241221314325451 its reverse (154523413122142), we get a palindrome (395744727447593).
The spelling of 241221314325451 in words is "two hundred forty-one trillion, two hundred twenty-one billion, three hundred fourteen million, three hundred twenty-five thousand, four hundred fifty-one".
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