Base | Representation |
---|---|
bin | 110110110110001110111110… |
… | …001111100010010001000011 |
3 | 1011122002112200220101110101201 |
4 | 312312032332033202101003 |
5 | 223104133002114120203 |
6 | 2213011333311442031 |
7 | 101544450104104351 |
oct | 6666167617422103 |
9 | 1148075626343351 |
10 | 241221439988803 |
11 | 6a95149027541a |
12 | 2307a3b8226317 |
13 | a47a112c59141 |
14 | 437d273c707d1 |
15 | 1cd4acad55e1d |
hex | db63be3e2443 |
241221439988803 has 2 divisors, whose sum is σ = 241221439988804. Its totient is φ = 241221439988802.
The previous prime is 241221439988783. The next prime is 241221439988833. The reversal of 241221439988803 is 308889934122142.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-241221439988803 is a prime.
It is a super-2 number, since 2×2412214399888032 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (241221439988833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120610719994401 + 120610719994402.
It is an arithmetic number, because the mean of its divisors is an integer number (120610719994402).
Almost surely, 2241221439988803 is an apocalyptic number.
241221439988803 is a deficient number, since it is larger than the sum of its proper divisors (1).
241221439988803 is an equidigital number, since it uses as much as digits as its factorization.
241221439988803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 47775744, while the sum is 64.
The spelling of 241221439988803 in words is "two hundred forty-one trillion, two hundred twenty-one billion, four hundred thirty-nine million, nine hundred eighty-eight thousand, eight hundred three".
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