Base | Representation |
---|---|
bin | 100011000110101000100… |
… | …110001111100010101001 |
3 | 22112121120200220201020102 |
4 | 203012220212033202221 |
5 | 304010400121003343 |
6 | 5044110413235145 |
7 | 336166113210626 |
oct | 43065046174251 |
9 | 8477520821212 |
10 | 2412305250473 |
11 | 850064474a78 |
12 | 32b630192ab5 |
13 | 146630352ac1 |
14 | 84a8300d34d |
15 | 42b39d413b8 |
hex | 231a898f8a9 |
2412305250473 has 2 divisors, whose sum is σ = 2412305250474. Its totient is φ = 2412305250472.
The previous prime is 2412305250457. The next prime is 2412305250527. The reversal of 2412305250473 is 3740525032142.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1947819383449 + 464485867024 = 1395643^2 + 681532^2 .
It is a cyclic number.
It is not a de Polignac number, because 2412305250473 - 24 = 2412305250457 is a prime.
It is not a weakly prime, because it can be changed into another prime (2412305450473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206152625236 + 1206152625237.
It is an arithmetic number, because the mean of its divisors is an integer number (1206152625237).
Almost surely, 22412305250473 is an apocalyptic number.
It is an amenable number.
2412305250473 is a deficient number, since it is larger than the sum of its proper divisors (1).
2412305250473 is an equidigital number, since it uses as much as digits as its factorization.
2412305250473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 201600, while the sum is 38.
The spelling of 2412305250473 in words is "two trillion, four hundred twelve billion, three hundred five million, two hundred fifty thousand, four hundred seventy-three".
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