Base | Representation |
---|---|
bin | 110110110110101101101011… |
… | …100001111100010000110101 |
3 | 1011122012200210210010101002221 |
4 | 312312231223201330100311 |
5 | 223110203013440341232 |
6 | 2213034425153202341 |
7 | 101550025142665231 |
oct | 6666555341742065 |
9 | 1148180723111087 |
10 | 241254412043317 |
11 | 6a964470121a52 |
12 | 2308487a5603b1 |
13 | a480268c9c97a |
14 | 4380ac0cc95c1 |
15 | 1cd58aa853897 |
hex | db6b6b87c435 |
241254412043317 has 2 divisors, whose sum is σ = 241254412043318. Its totient is φ = 241254412043316.
The previous prime is 241254412043257. The next prime is 241254412043327. The reversal of 241254412043317 is 713340214452142.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 127065333450276 + 114189078593041 = 11272326^2 + 10685929^2 .
It is a cyclic number.
It is not a de Polignac number, because 241254412043317 - 27 = 241254412043189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241254412043327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120627206021658 + 120627206021659.
It is an arithmetic number, because the mean of its divisors is an integer number (120627206021659).
Almost surely, 2241254412043317 is an apocalyptic number.
It is an amenable number.
241254412043317 is a deficient number, since it is larger than the sum of its proper divisors (1).
241254412043317 is an equidigital number, since it uses as much as digits as its factorization.
241254412043317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 645120, while the sum is 43.
Adding to 241254412043317 its reverse (713340214452142), we get a palindrome (954594626495459).
The spelling of 241254412043317 in words is "two hundred forty-one trillion, two hundred fifty-four billion, four hundred twelve million, forty-three thousand, three hundred seventeen".
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