Search a number
-
+
241254412043317 is a prime number
BaseRepresentation
bin110110110110101101101011…
…100001111100010000110101
31011122012200210210010101002221
4312312231223201330100311
5223110203013440341232
62213034425153202341
7101550025142665231
oct6666555341742065
91148180723111087
10241254412043317
116a964470121a52
122308487a5603b1
13a480268c9c97a
144380ac0cc95c1
151cd58aa853897
hexdb6b6b87c435

241254412043317 has 2 divisors, whose sum is σ = 241254412043318. Its totient is φ = 241254412043316.

The previous prime is 241254412043257. The next prime is 241254412043327. The reversal of 241254412043317 is 713340214452142.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127065333450276 + 114189078593041 = 11272326^2 + 10685929^2 .

It is a cyclic number.

It is not a de Polignac number, because 241254412043317 - 27 = 241254412043189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (241254412043327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120627206021658 + 120627206021659.

It is an arithmetic number, because the mean of its divisors is an integer number (120627206021659).

Almost surely, 2241254412043317 is an apocalyptic number.

It is an amenable number.

241254412043317 is a deficient number, since it is larger than the sum of its proper divisors (1).

241254412043317 is an equidigital number, since it uses as much as digits as its factorization.

241254412043317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 645120, while the sum is 43.

Adding to 241254412043317 its reverse (713340214452142), we get a palindrome (954594626495459).

The spelling of 241254412043317 in words is "two hundred forty-one trillion, two hundred fifty-four billion, four hundred twelve million, forty-three thousand, three hundred seventeen".