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24131055013159 is a prime number
BaseRepresentation
bin1010111110010011100101…
…11101100100110100100111
310011102220110201021200012011
411133021302331210310213
511130330400040410114
6123153353103535051
75040261016200343
oct537116275446447
9104386421250164
1024131055013159
117763a17506836
1228589155ba487
131060719713323
145d5d40c14623
152bca866011c4
hex15f272f64d27

24131055013159 has 2 divisors, whose sum is σ = 24131055013160. Its totient is φ = 24131055013158.

The previous prime is 24131055013127. The next prime is 24131055013189. The reversal of 24131055013159 is 95131055013142.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 24131055013159 - 25 = 24131055013127 is a prime.

It is a super-2 number, since 2×241310550131592 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (24131055013189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12065527506579 + 12065527506580.

It is an arithmetic number, because the mean of its divisors is an integer number (12065527506580).

Almost surely, 224131055013159 is an apocalyptic number.

24131055013159 is a deficient number, since it is larger than the sum of its proper divisors (1).

24131055013159 is an equidigital number, since it uses as much as digits as its factorization.

24131055013159 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81000, while the sum is 40.

The spelling of 24131055013159 in words is "twenty-four trillion, one hundred thirty-one billion, fifty-five million, thirteen thousand, one hundred fifty-nine".