Base | Representation |
---|---|
bin | 1010111110010011100101… |
… | …11101100100110100100111 |
3 | 10011102220110201021200012011 |
4 | 11133021302331210310213 |
5 | 11130330400040410114 |
6 | 123153353103535051 |
7 | 5040261016200343 |
oct | 537116275446447 |
9 | 104386421250164 |
10 | 24131055013159 |
11 | 7763a17506836 |
12 | 28589155ba487 |
13 | 1060719713323 |
14 | 5d5d40c14623 |
15 | 2bca866011c4 |
hex | 15f272f64d27 |
24131055013159 has 2 divisors, whose sum is σ = 24131055013160. Its totient is φ = 24131055013158.
The previous prime is 24131055013127. The next prime is 24131055013189. The reversal of 24131055013159 is 95131055013142.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 24131055013159 - 25 = 24131055013127 is a prime.
It is a super-2 number, since 2×241310550131592 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (24131055013189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12065527506579 + 12065527506580.
It is an arithmetic number, because the mean of its divisors is an integer number (12065527506580).
Almost surely, 224131055013159 is an apocalyptic number.
24131055013159 is a deficient number, since it is larger than the sum of its proper divisors (1).
24131055013159 is an equidigital number, since it uses as much as digits as its factorization.
24131055013159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 40.
The spelling of 24131055013159 in words is "twenty-four trillion, one hundred thirty-one billion, fifty-five million, thirteen thousand, one hundred fifty-nine".
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