Base | Representation |
---|---|
bin | 100011000111011101111… |
… | …100010100110000100001 |
3 | 22112200220001222110100021 |
4 | 203013131330110300201 |
5 | 304014213224401312 |
6 | 5044335303553441 |
7 | 336230231343631 |
oct | 43073574246041 |
9 | 8480801873307 |
10 | 2413200231457 |
11 | 850483689484 |
12 | 32b83ba5b881 |
13 | 1467438acb52 |
14 | 84b29c206c1 |
15 | 42b8d6cac07 |
hex | 231ddf14c21 |
2413200231457 has 2 divisors, whose sum is σ = 2413200231458. Its totient is φ = 2413200231456.
The previous prime is 2413200231419. The next prime is 2413200231517. The reversal of 2413200231457 is 7541320023142.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2413147871761 + 52359696 = 1553431^2 + 7236^2 .
It is a cyclic number.
It is not a de Polignac number, because 2413200231457 - 219 = 2413199707169 is a prime.
It is not a weakly prime, because it can be changed into another prime (2413200231257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206600115728 + 1206600115729.
It is an arithmetic number, because the mean of its divisors is an integer number (1206600115729).
Almost surely, 22413200231457 is an apocalyptic number.
It is an amenable number.
2413200231457 is a deficient number, since it is larger than the sum of its proper divisors (1).
2413200231457 is an equidigital number, since it uses as much as digits as its factorization.
2413200231457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 34.
Adding to 2413200231457 its reverse (7541320023142), we get a palindrome (9954520254599).
The spelling of 2413200231457 in words is "two trillion, four hundred thirteen billion, two hundred million, two hundred thirty-one thousand, four hundred fifty-seven".
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