Base | Representation |
---|---|
bin | 100011000111100011111… |
… | …110011010001110100011 |
3 | 22112201011010102110100021 |
4 | 203013203332122032203 |
5 | 304014420132111233 |
6 | 5044353321134311 |
7 | 336232600535524 |
oct | 43074376321643 |
9 | 8481133373307 |
10 | 2413301441443 |
11 | 850525826aa2 |
12 | 32b86992a397 |
13 | 14675b858309 |
14 | 84b3944884b |
15 | 42b9751de2d |
hex | 231e3f9a3a3 |
2413301441443 has 2 divisors, whose sum is σ = 2413301441444. Its totient is φ = 2413301441442.
The previous prime is 2413301441209. The next prime is 2413301441449. The reversal of 2413301441443 is 3441441033142.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2413301441443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2413301441399 and 2413301441408.
It is not a weakly prime, because it can be changed into another prime (2413301441449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206650720721 + 1206650720722.
It is an arithmetic number, because the mean of its divisors is an integer number (1206650720722).
Almost surely, 22413301441443 is an apocalyptic number.
2413301441443 is a deficient number, since it is larger than the sum of its proper divisors (1).
2413301441443 is an equidigital number, since it uses as much as digits as its factorization.
2413301441443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 2413301441443 its reverse (3441441033142), we get a palindrome (5854742474585).
The spelling of 2413301441443 in words is "two trillion, four hundred thirteen billion, three hundred one million, four hundred forty-one thousand, four hundred forty-three".
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