Base | Representation |
---|---|
bin | 100011000111100110010… |
… | …001100000010010110111 |
3 | 22112201020210222111202011 |
4 | 203013212101200102313 |
5 | 304020010020021323 |
6 | 5044401215425051 |
7 | 336233546355436 |
oct | 43074621402267 |
9 | 8481223874664 |
10 | 2413340001463 |
11 | 850545573786 |
12 | 32b87a825187 |
13 | 1467668395b1 |
14 | 84b4060511d |
15 | 42b9aad920d |
hex | 231e64604b7 |
2413340001463 has 2 divisors, whose sum is σ = 2413340001464. Its totient is φ = 2413340001462.
The previous prime is 2413340001437. The next prime is 2413340001481. The reversal of 2413340001463 is 3641000433142.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2413340001463 - 213 = 2413339993271 is a prime.
It is a super-2 number, since 2×24133400014632 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2413340001433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206670000731 + 1206670000732.
It is an arithmetic number, because the mean of its divisors is an integer number (1206670000732).
Almost surely, 22413340001463 is an apocalyptic number.
2413340001463 is a deficient number, since it is larger than the sum of its proper divisors (1).
2413340001463 is an equidigital number, since it uses as much as digits as its factorization.
2413340001463 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 31.
The spelling of 2413340001463 in words is "two trillion, four hundred thirteen billion, three hundred forty million, one thousand, four hundred sixty-three".
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