241413125311 has 2 divisors, whose sum is σ = 241413125312. Its totient is φ = 241413125310.

The previous prime is 241413125209. The next prime is 241413125321. The reversal of 241413125311 is 113521314142.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-241413125311 is a prime.

It is a super-3 number, since 3×241413125311³ (a number of 35 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 241413125311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (241413125321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120706562655 + 120706562656.

It is an arithmetic number, because the mean of its divisors is an integer number (120706562656).

Almost surely, 2^241413125311 is an apocalyptic number.

241413125311 is a deficient number, since it is larger than the sum of its proper divisors (1).

241413125311 is an equidigital number, since it uses as much as digits as its factorization.

241413125311 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2880, while the sum is 28.

Adding to 241413125311 its reverse (113521314142), we get a palindrome (354934439453).

The spelling of 241413125311 in words is "two hundred forty-one billion, four hundred thirteen million, one hundred twenty-five thousand, three hundred eleven".