Base | Representation |
---|---|
bin | 110110111001001001000111… |
… | …000000110011111111001001 |
3 | 1011122210122120201002122110121 |
4 | 312321021013000303333021 |
5 | 223120421312043302213 |
6 | 2213243225431543241 |
7 | 101565053643412555 |
oct | 6671110700637711 |
9 | 1148718521078417 |
10 | 241421303103433 |
11 | 6aa19221841612 |
12 | 230b1095b2ab21 |
13 | a492c14abb84b |
14 | 4388bd3abc865 |
15 | 1cd9dc728b88d |
hex | db9247033fc9 |
241421303103433 has 2 divisors, whose sum is σ = 241421303103434. Its totient is φ = 241421303103432.
The previous prime is 241421303103401. The next prime is 241421303103437. The reversal of 241421303103433 is 334301303124142.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 241398462222009 + 22840881424 = 15537003^2 + 151132^2 .
It is a cyclic number.
It is not a de Polignac number, because 241421303103433 - 25 = 241421303103401 is a prime.
It is not a weakly prime, because it can be changed into another prime (241421303103437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120710651551716 + 120710651551717.
It is an arithmetic number, because the mean of its divisors is an integer number (120710651551717).
Almost surely, 2241421303103433 is an apocalyptic number.
It is an amenable number.
241421303103433 is a deficient number, since it is larger than the sum of its proper divisors (1).
241421303103433 is an equidigital number, since it uses as much as digits as its factorization.
241421303103433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 241421303103433 its reverse (334301303124142), we get a palindrome (575722606227575).
The spelling of 241421303103433 in words is "two hundred forty-one trillion, four hundred twenty-one billion, three hundred three million, one hundred three thousand, four hundred thirty-three".
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