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2414434303133 is a prime number
BaseRepresentation
bin100011001000100111011…
…111111011110010011101
322112211002002002210102122
4203020213133323302131
5304024230140200013
65045101550232325
7336302634646346
oct43104737736235
98484062083378
102414434303133
11850a57246826
1232bb251b56a5
131468ac473688
1484c05a9d0cd
1542c11be6a08
hex232277fbc9d

2414434303133 has 2 divisors, whose sum is σ = 2414434303134. Its totient is φ = 2414434303132.

The previous prime is 2414434303123. The next prime is 2414434303147. The reversal of 2414434303133 is 3313034344142.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2357815528324 + 56618774809 = 1535518^2 + 237947^2 .

It is a cyclic number.

It is not a de Polignac number, because 2414434303133 - 214 = 2414434286749 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2414434303093 and 2414434303102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2414434303123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1207217151566 + 1207217151567.

It is an arithmetic number, because the mean of its divisors is an integer number (1207217151567).

Almost surely, 22414434303133 is an apocalyptic number.

It is an amenable number.

2414434303133 is a deficient number, since it is larger than the sum of its proper divisors (1).

2414434303133 is an equidigital number, since it uses as much as digits as its factorization.

2414434303133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 2414434303133 its reverse (3313034344142), we get a palindrome (5727468647275).

The spelling of 2414434303133 in words is "two trillion, four hundred fourteen billion, four hundred thirty-four million, three hundred three thousand, one hundred thirty-three".