Base | Representation |
---|---|
bin | 1110000110000110000… |
… | …1011001000111000011 |
3 | 212011001011001121200002 |
4 | 3201201201121013003 |
5 | 12431413000442011 |
6 | 303124423150215 |
7 | 23331544456124 |
oct | 3414141310703 |
9 | 764034047602 |
10 | 242154312131 |
11 | 93773883896 |
12 | 3ab20ba536b |
13 | 19ab17c7634 |
14 | ba1283604b |
15 | 6474150c3b |
hex | 38618591c3 |
242154312131 has 2 divisors, whose sum is σ = 242154312132. Its totient is φ = 242154312130.
The previous prime is 242154312041. The next prime is 242154312199. The reversal of 242154312131 is 131213451242.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 242154312131 - 218 = 242154049987 is a prime.
It is a super-2 number, since 2×2421543121312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 242154312094 and 242154312103.
It is not a weakly prime, because it can be changed into another prime (242154312031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121077156065 + 121077156066.
It is an arithmetic number, because the mean of its divisors is an integer number (121077156066).
Almost surely, 2242154312131 is an apocalyptic number.
242154312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
242154312131 is an equidigital number, since it uses as much as digits as its factorization.
242154312131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5760, while the sum is 29.
Adding to 242154312131 its reverse (131213451242), we get a palindrome (373367763373).
The spelling of 242154312131 in words is "two hundred forty-two billion, one hundred fifty-four million, three hundred twelve thousand, one hundred thirty-one".
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