Base | Representation |
---|---|
bin | 1011000000111111010000… |
… | …00000011001010110110101 |
3 | 10011202201100100210110220101 |
4 | 11200133220000121112311 |
5 | 11133333120012000432 |
6 | 123303553533234101 |
7 | 5050032541152145 |
oct | 540375000312665 |
9 | 104681310713811 |
10 | 24223213000117 |
11 | 779a00927141a |
12 | 2872755032931 |
13 | 1069315647061 |
14 | 5da5a4574925 |
15 | 2c017c14b4e7 |
hex | 1607e80195b5 |
24223213000117 has 2 divisors, whose sum is σ = 24223213000118. Its totient is φ = 24223213000116.
The previous prime is 24223213000081. The next prime is 24223213000139. The reversal of 24223213000117 is 71100031232242.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 24206311440081 + 16901560036 = 4919991^2 + 130006^2 .
It is a cyclic number.
It is not a de Polignac number, because 24223213000117 - 223 = 24223204611509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (24223213090117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12111606500058 + 12111606500059.
It is an arithmetic number, because the mean of its divisors is an integer number (12111606500059).
Almost surely, 224223213000117 is an apocalyptic number.
It is an amenable number.
24223213000117 is a deficient number, since it is larger than the sum of its proper divisors (1).
24223213000117 is an equidigital number, since it uses as much as digits as its factorization.
24223213000117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 24223213000117 its reverse (71100031232242), we get a palindrome (95323244232359).
The spelling of 24223213000117 in words is "twenty-four trillion, two hundred twenty-three billion, two hundred thirteen million, one hundred seventeen", and thus it is an aban number.
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