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242313433 is a prime number
BaseRepresentation
bin11100111000101…
…10100011011001
3121212221210112121
432130112203121
5444013012213
640013341241
76001426105
oct1634264331
9555853477
10242313433
1111486373a
1269197821
133b280b3b
1424278905
151641688d
hexe7168d9

242313433 has 2 divisors, whose sum is σ = 242313434. Its totient is φ = 242313432.

The previous prime is 242313419. The next prime is 242313457. The reversal of 242313433 is 334313242.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 241118784 + 1194649 = 15528^2 + 1093^2 .

It is a cyclic number.

It is not a de Polignac number, because 242313433 - 29 = 242312921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 242313398 and 242313407.

It is not a weakly prime, because it can be changed into another prime (242316433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121156716 + 121156717.

It is an arithmetic number, because the mean of its divisors is an integer number (121156717).

Almost surely, 2242313433 is an apocalyptic number.

It is an amenable number.

242313433 is a deficient number, since it is larger than the sum of its proper divisors (1).

242313433 is an equidigital number, since it uses as much as digits as its factorization.

242313433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5184, while the sum is 25.

The square root of 242313433 is about 15566.4200444418. The cubic root of 242313433 is about 623.4368901190.

Adding to 242313433 its reverse (334313242), we get a palindrome (576626675).

The spelling of 242313433 in words is "two hundred forty-two million, three hundred thirteen thousand, four hundred thirty-three".