Base | Representation |
---|---|
bin | 1011000001100001100100… |
… | …11011110011001110001001 |
3 | 10011211110220200101200022202 |
4 | 11200300302123303032021 |
5 | 11134133340220121423 |
6 | 123320242325325545 |
7 | 5051254322325545 |
oct | 540606233631611 |
9 | 104743820350282 |
10 | 24241641567113 |
11 | 77a6905760583 |
12 | 28762388668b5 |
13 | 106ac915ab879 |
14 | 5db431c80a25 |
15 | 2c08a9e5c728 |
hex | 160c326f3389 |
24241641567113 has 2 divisors, whose sum is σ = 24241641567114. Its totient is φ = 24241641567112.
The previous prime is 24241641567071. The next prime is 24241641567161. The reversal of 24241641567113 is 31176514614242.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24138325607929 + 103315959184 = 4913077^2 + 321428^2 .
It is a cyclic number.
It is not a de Polignac number, because 24241641567113 - 240 = 23142129939337 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (24241641567163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12120820783556 + 12120820783557.
It is an arithmetic number, because the mean of its divisors is an integer number (12120820783557).
Almost surely, 224241641567113 is an apocalyptic number.
It is an amenable number.
24241641567113 is a deficient number, since it is larger than the sum of its proper divisors (1).
24241641567113 is an equidigital number, since it uses as much as digits as its factorization.
24241641567113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 967680, while the sum is 47.
The spelling of 24241641567113 in words is "twenty-four trillion, two hundred forty-one billion, six hundred forty-one million, five hundred sixty-seven thousand, one hundred thirteen".
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