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242422142113 is a prime number
BaseRepresentation
bin1110000111000101111…
…1000101010010100001
3212011201211000210100001
43201301133011102201
512432440032021423
6303211151500001
723341306131424
oct3416137052241
9764654023301
10242422142113
11938a0a85488
123ab96827601
1319b25140808
14ba3a2339bb
15648c907cad
hex38717c54a1

242422142113 has 2 divisors, whose sum is σ = 242422142114. Its totient is φ = 242422142112.

The previous prime is 242422142111. The next prime is 242422142117. The reversal of 242422142113 is 311241224242.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 209533231504 + 32888910609 = 457748^2 + 181353^2 .

It is a cyclic number.

It is not a de Polignac number, because 242422142113 - 21 = 242422142111 is a prime.

It is a super-3 number, since 3×2424221421133 (a number of 35 digits) contains 333 as substring.

Together with 242422142111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (242422142111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121211071056 + 121211071057.

It is an arithmetic number, because the mean of its divisors is an integer number (121211071057).

Almost surely, 2242422142113 is an apocalyptic number.

It is an amenable number.

242422142113 is a deficient number, since it is larger than the sum of its proper divisors (1).

242422142113 is an equidigital number, since it uses as much as digits as its factorization.

242422142113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6144, while the sum is 28.

Adding to 242422142113 its reverse (311241224242), we get a palindrome (553663366355).

The spelling of 242422142113 in words is "two hundred forty-two billion, four hundred twenty-two million, one hundred forty-two thousand, one hundred thirteen".