Base | Representation |
---|---|
bin | 100011010011100000101… |
… | …101010100010111101100 |
3 | 22120221021021111112211102 |
4 | 203103200231110113230 |
5 | 304222204132444434 |
6 | 5054314402342232 |
7 | 340165541520251 |
oct | 43234055242754 |
9 | 8527237445742 |
10 | 2426131531244 |
11 | 855a0a0003a3 |
12 | 33224a65a978 |
13 | 147a24979825 |
14 | 855d53c5428 |
15 | 43198aac07e |
hex | 234e0b545ec |
2426131531244 has 24 divisors (see below), whose sum is σ = 4247874178128. Its totient is φ = 1212453325760.
The previous prime is 2426131531189. The next prime is 2426131531247. The reversal of 2426131531244 is 4421351316242.
It is a super-2 number, since 2×24261315312442 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2426131531198 and 2426131531207.
It is not an unprimeable number, because it can be changed into a prime (2426131531247) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 150767639 + ... + 150783729.
It is an arithmetic number, because the mean of its divisors is an integer number (176994757422).
Almost surely, 22426131531244 is an apocalyptic number.
It is an amenable number.
2426131531244 is a deficient number, since it is larger than the sum of its proper divisors (1821742646884).
2426131531244 is a wasteful number, since it uses less digits than its factorization.
2426131531244 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32785 (or 32783 counting only the distinct ones).
The product of its digits is 138240, while the sum is 38.
Adding to 2426131531244 its reverse (4421351316242), we get a palindrome (6847482847486).
The spelling of 2426131531244 in words is "two trillion, four hundred twenty-six billion, one hundred thirty-one million, five hundred thirty-one thousand, two hundred forty-four".
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