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243034331121353 is a prime number
BaseRepresentation
bin110111010000100111010110…
…111110011000011011001001
31011212111212002101220000021002
4313100213112332120123021
5223323333302231340403
62220520232544224345
7102122436200346302
oct6720472676303311
91155455071800232
10243034331121353
1170490310031762
122331182190b0b5
13a57c067b46315
144402cd27497a9
151d16d324a9188
hexdd09d6f986c9

243034331121353 has 2 divisors, whose sum is σ = 243034331121354. Its totient is φ = 243034331121352.

The previous prime is 243034331121341. The next prime is 243034331121451. The reversal of 243034331121353 is 353121133430342.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 228949945112464 + 14084386008889 = 15131092^2 + 3752917^2 .

It is a cyclic number.

It is not a de Polignac number, because 243034331121353 - 218 = 243034330859209 is a prime.

It is a super-2 number, since 2×2430343311213532 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (243034331121053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121517165560676 + 121517165560677.

It is an arithmetic number, because the mean of its divisors is an integer number (121517165560677).

Almost surely, 2243034331121353 is an apocalyptic number.

It is an amenable number.

243034331121353 is a deficient number, since it is larger than the sum of its proper divisors (1).

243034331121353 is an equidigital number, since it uses as much as digits as its factorization.

243034331121353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 233280, while the sum is 38.

Adding to 243034331121353 its reverse (353121133430342), we get a palindrome (596155464551695).

The spelling of 243034331121353 in words is "two hundred forty-three trillion, thirty-four billion, three hundred thirty-one million, one hundred twenty-one thousand, three hundred fifty-three".