Base | Representation |
---|---|
bin | 10110101001000011… |
… | …011111111010010001 |
3 | 2022202021121222221201 |
4 | 112221003133322101 |
5 | 344242120244441 |
6 | 15100211151201 |
7 | 1520310652444 |
oct | 265103377221 |
9 | 68667558851 |
10 | 24311103121 |
11 | a345a90668 |
12 | 48658a5501 |
13 | 23a58b3b26 |
14 | 1268a9d65b |
15 | 974494c31 |
hex | 5a90dfe91 |
24311103121 has 2 divisors, whose sum is σ = 24311103122. Its totient is φ = 24311103120.
The previous prime is 24311103119. The next prime is 24311103163. The reversal of 24311103121 is 12130111342.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19498212496 + 4812890625 = 139636^2 + 69375^2 .
It is a cyclic number.
It is not a de Polignac number, because 24311103121 - 21 = 24311103119 is a prime.
Together with 24311103119, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (24311103821) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12155551560 + 12155551561.
It is an arithmetic number, because the mean of its divisors is an integer number (12155551561).
Almost surely, 224311103121 is an apocalyptic number.
It is an amenable number.
24311103121 is a deficient number, since it is larger than the sum of its proper divisors (1).
24311103121 is an equidigital number, since it uses as much as digits as its factorization.
24311103121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 24311103121 its reverse (12130111342), we get a palindrome (36441214463).
The spelling of 24311103121 in words is "twenty-four billion, three hundred eleven million, one hundred three thousand, one hundred twenty-one".
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