Base | Representation |
---|---|
bin | 1110001001101110111… |
… | …1001111010010011001 |
3 | 212020120012220112120221 |
4 | 3202123233033102121 |
5 | 12440413020123231 |
6 | 303405353320041 |
7 | 23365004401201 |
oct | 3423357172231 |
9 | 766505815527 |
10 | 243131020441 |
11 | 94125139241 |
12 | 3b154106021 |
13 | 19c08c6b04a |
14 | baa643d401 |
15 | 64cec80d11 |
hex | 389bbcf499 |
243131020441 has 2 divisors, whose sum is σ = 243131020442. Its totient is φ = 243131020440.
The previous prime is 243131020423. The next prime is 243131020453. The reversal of 243131020441 is 144020131342.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 227028425625 + 16102594816 = 476475^2 + 126896^2 .
It is a cyclic number.
It is not a de Polignac number, because 243131020441 - 211 = 243131018393 is a prime.
It is a super-2 number, since 2×2431310204412 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (243131020421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121565510220 + 121565510221.
It is an arithmetic number, because the mean of its divisors is an integer number (121565510221).
Almost surely, 2243131020441 is an apocalyptic number.
It is an amenable number.
243131020441 is a deficient number, since it is larger than the sum of its proper divisors (1).
243131020441 is an equidigital number, since it uses as much as digits as its factorization.
243131020441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 243131020441 its reverse (144020131342), we get a palindrome (387151151783).
The spelling of 243131020441 in words is "two hundred forty-three billion, one hundred thirty-one million, twenty thousand, four hundred forty-one".
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