Base | Representation |
---|---|
bin | 100011011000010101011… |
… | …111100111111011101111 |
3 | 22121102122022122202200011 |
4 | 203120111133213323233 |
5 | 304313311344213403 |
6 | 5100532424114051 |
7 | 340441115605414 |
oct | 43302537477357 |
9 | 8542568582604 |
10 | 2431312101103 |
11 | 85812832a196 |
12 | 333255605927 |
13 | 14836c04b792 |
14 | 8596744c10b |
15 | 4339d7d0a6d |
hex | 236157e7eef |
2431312101103 has 2 divisors, whose sum is σ = 2431312101104. Its totient is φ = 2431312101102.
The previous prime is 2431312101091. The next prime is 2431312101149. The reversal of 2431312101103 is 3011012131342.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2431312101103 - 221 = 2431310003951 is a prime.
It is a super-2 number, since 2×24313121011032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2431312101173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1215656050551 + 1215656050552.
It is an arithmetic number, because the mean of its divisors is an integer number (1215656050552).
Almost surely, 22431312101103 is an apocalyptic number.
2431312101103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2431312101103 is an equidigital number, since it uses as much as digits as its factorization.
2431312101103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 2431312101103 its reverse (3011012131342), we get a palindrome (5442324232445).
The spelling of 2431312101103 in words is "two trillion, four hundred thirty-one billion, three hundred twelve million, one hundred one thousand, one hundred three".
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