Base | Representation |
---|---|
bin | 1110001001101111000… |
… | …1001100001011101011 |
3 | 212020120020212112022222 |
4 | 3202123301030023223 |
5 | 12440413133011021 |
6 | 303405412304255 |
7 | 23365011631514 |
oct | 3423361141353 |
9 | 766506775288 |
10 | 243131532011 |
11 | 94125458625 |
12 | 3b15431208b |
13 | 19c090b9b54 |
14 | baa6533a0b |
15 | 64ced326ab |
hex | 389bc4c2eb |
243131532011 has 2 divisors, whose sum is σ = 243131532012. Its totient is φ = 243131532010.
The previous prime is 243131532001. The next prime is 243131532013. The reversal of 243131532011 is 110235131342.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 243131532011 - 222 = 243127337707 is a prime.
It is a super-2 number, since 2×2431315320112 (a number of 24 digits) contains 22 as substring.
Together with 243131532013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (243131532013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121565766005 + 121565766006.
It is an arithmetic number, because the mean of its divisors is an integer number (121565766006).
Almost surely, 2243131532011 is an apocalyptic number.
243131532011 is a deficient number, since it is larger than the sum of its proper divisors (1).
243131532011 is an equidigital number, since it uses as much as digits as its factorization.
243131532011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 243131532011 its reverse (110235131342), we get a palindrome (353366663353).
The spelling of 243131532011 in words is "two hundred forty-three billion, one hundred thirty-one million, five hundred thirty-two thousand, eleven".
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