Base | Representation |
---|---|
bin | 110111010010000010011100… |
… | …111001100101011010010110 |
3 | 1011212212012112221111100020102 |
4 | 313102002130321211122112 |
5 | 223331434111101024420 |
6 | 2221033210314134102 |
7 | 102132501052030010 |
oct | 6722023471453226 |
9 | 1155765487440212 |
10 | 243132141033110 |
11 | 7051884219807a |
12 | 2332877a121332 |
13 | a5883549b4a54 |
14 | 440793098d1b0 |
15 | 1d196592d3a75 |
hex | dd209ce65696 |
243132141033110 has 16 divisors (see below), whose sum is σ = 500157547268256. Its totient is φ = 83359591211328.
The previous prime is 243132141033107. The next prime is 243132141033137. The reversal of 243132141033110 is 11330141231342.
243132141033110 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×2431321410331102 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1736658150167 + ... + 1736658150306.
It is an arithmetic number, because the mean of its divisors is an integer number (31259846704266).
Almost surely, 2243132141033110 is an apocalyptic number.
243132141033110 is an abundant number, since it is smaller than the sum of its proper divisors (257025406235146).
243132141033110 is a wasteful number, since it uses less digits than its factorization.
243132141033110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3473316300487.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 243132141033110 its reverse (11330141231342), we get a palindrome (254462282264452).
The spelling of 243132141033110 in words is "two hundred forty-three trillion, one hundred thirty-two billion, one hundred forty-one million, thirty-three thousand, one hundred ten".
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