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243142011631 is a prime number
BaseRepresentation
bin1110001001110001100…
…1001010101011101111
3212020120222120221200001
43202130121022223233
512440423323333011
6303410425045131
723365166666401
oct3423431125357
9766528527601
10243142011631
1194130366072
123b1579267a7
1319c0b318acc
14baa7aa0b71
1564d0c027c1
hex389c64aaef

243142011631 has 2 divisors, whose sum is σ = 243142011632. Its totient is φ = 243142011630.

The previous prime is 243142011599. The next prime is 243142011649. The reversal of 243142011631 is 136110241342.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 243142011631 - 25 = 243142011599 is a prime.

It is a super-2 number, since 2×2431420116312 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 243142011631.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243142017631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121571005815 + 121571005816.

It is an arithmetic number, because the mean of its divisors is an integer number (121571005816).

Almost surely, 2243142011631 is an apocalyptic number.

243142011631 is a deficient number, since it is larger than the sum of its proper divisors (1).

243142011631 is an equidigital number, since it uses as much as digits as its factorization.

243142011631 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 243142011631 its reverse (136110241342), we get a palindrome (379252252973).

The spelling of 243142011631 in words is "two hundred forty-three billion, one hundred forty-two million, eleven thousand, six hundred thirty-one".