Base | Representation |
---|---|
bin | 100011011001011000001… |
… | …100011100100000101011 |
3 | 22121112112022100012010101 |
4 | 203121120030130200223 |
5 | 304323104333201201 |
6 | 5101235441130231 |
7 | 340510624415143 |
oct | 43313014344053 |
9 | 8545468305111 |
10 | 2432431147051 |
11 | 858651a72a54 |
12 | 333508329977 |
13 | 1484b9b3a549 |
14 | 85a31d07923 |
15 | 43416b79d01 |
hex | 2365831c82b |
2432431147051 has 2 divisors, whose sum is σ = 2432431147052. Its totient is φ = 2432431147050.
The previous prime is 2432431147049. The next prime is 2432431147121. The reversal of 2432431147051 is 1507411342342.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2432431147051 - 21 = 2432431147049 is a prime.
Together with 2432431147049, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 2432431147051.
It is not a weakly prime, because it can be changed into another prime (2432431147021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1216215573525 + 1216215573526.
It is an arithmetic number, because the mean of its divisors is an integer number (1216215573526).
Almost surely, 22432431147051 is an apocalyptic number.
2432431147051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2432431147051 is an equidigital number, since it uses as much as digits as its factorization.
2432431147051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 37.
Adding to 2432431147051 its reverse (1507411342342), we get a palindrome (3939842489393).
The spelling of 2432431147051 in words is "two trillion, four hundred thirty-two billion, four hundred thirty-one million, one hundred forty-seven thousand, fifty-one".
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