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24340344141131 is a prime number
BaseRepresentation
bin1011000100011001011011…
…00100001111010101001011
310012011220200102200221201022
411202030231210033111023
511142243011100004011
6123433444424143055
75061350263344164
oct542145544172513
9105156612627638
1024340344141131
1178347557972a7
1228913a4007a8b
131077391374b15
1460211689076b
152c32353148db
hex16232d90f54b

24340344141131 has 2 divisors, whose sum is σ = 24340344141132. Its totient is φ = 24340344141130.

The previous prime is 24340344141107. The next prime is 24340344141133. The reversal of 24340344141131 is 13114144304342.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-24340344141131 is a prime.

It is a super-2 number, since 2×243403441411312 (a number of 28 digits) contains 22 as substring.

Together with 24340344141133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 24340344141091 and 24340344141100.

It is not a weakly prime, because it can be changed into another prime (24340344141133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12170172070565 + 12170172070566.

It is an arithmetic number, because the mean of its divisors is an integer number (12170172070566).

Almost surely, 224340344141131 is an apocalyptic number.

24340344141131 is a deficient number, since it is larger than the sum of its proper divisors (1).

24340344141131 is an equidigital number, since it uses as much as digits as its factorization.

24340344141131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 24340344141131 its reverse (13114144304342), we get a palindrome (37454488445473).

The spelling of 24340344141131 in words is "twenty-four trillion, three hundred forty billion, three hundred forty-four million, one hundred forty-one thousand, one hundred thirty-one".