Base | Representation |
---|---|
bin | 100011011011001000011… |
… | …100000111001101100111 |
3 | 22121201101112211101111111 |
4 | 203123020130013031213 |
5 | 304340433430133221 |
6 | 5102150351445451 |
7 | 340605402106543 |
oct | 43331034071547 |
9 | 8551345741444 |
10 | 2434314302311 |
11 | 859428a63411 |
12 | 333952b26887 |
13 | 14872a023bb8 |
14 | 85b70068a23 |
15 | 434c715bbe1 |
hex | 236c8707367 |
2434314302311 has 2 divisors, whose sum is σ = 2434314302312. Its totient is φ = 2434314302310.
The previous prime is 2434314302281. The next prime is 2434314302339. The reversal of 2434314302311 is 1132034134342.
2434314302311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2434314302311 - 27 = 2434314302183 is a prime.
It is a super-2 number, since 2×24343143023112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2434314302351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1217157151155 + 1217157151156.
It is an arithmetic number, because the mean of its divisors is an integer number (1217157151156).
Almost surely, 22434314302311 is an apocalyptic number.
2434314302311 is a deficient number, since it is larger than the sum of its proper divisors (1).
2434314302311 is an equidigital number, since it uses as much as digits as its factorization.
2434314302311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 2434314302311 its reverse (1132034134342), we get a palindrome (3566348436653).
The spelling of 2434314302311 in words is "two trillion, four hundred thirty-four billion, three hundred fourteen million, three hundred two thousand, three hundred eleven".
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