Base | Representation |
---|---|
bin | 110111010110011011101101… |
… | …000101011011000001101100 |
3 | 1011220221002001100120210221001 |
4 | 313112123231011123001230 |
5 | 223401411101302234200 |
6 | 2221424033004050044 |
7 | 102163351530063322 |
oct | 6726335505330154 |
9 | 1156832040523831 |
10 | 243434134024300 |
11 | 7062492238412a |
12 | 233771bab33924 |
13 | a5aa9816a578b |
14 | 44183bc683d12 |
15 | 1d2243191d76a |
hex | dd66ed15b06c |
243434134024300 has 18 divisors (see below), whose sum is σ = 528252070832948. Its totient is φ = 97373653609680.
The previous prime is 243434134024267. The next prime is 243434134024327. The reversal of 243434134024300 is 3420431434342.
It is a self number, because there is not a number n which added to its sum of digits gives 243434134024300.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1217170670022 + ... + 1217170670221.
Almost surely, 2243434134024300 is an apocalyptic number.
243434134024300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
243434134024300 is an abundant number, since it is smaller than the sum of its proper divisors (284817936808648).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
243434134024300 is a wasteful number, since it uses less digits than its factorization.
243434134024300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2434341340257 (or 2434341340250 counting only the distinct ones).
The product of its (nonzero) digits is 331776, while the sum is 37.
Adding to 243434134024300 its reverse (3420431434342), we get a palindrome (246854565458642).
The spelling of 243434134024300 in words is "two hundred forty-three trillion, four hundred thirty-four billion, one hundred thirty-four million, twenty-four thousand, three hundred".
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