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243453134314001 is a prime number
BaseRepresentation
bin110111010110101101011001…
…100101110001101000010001
31011220222220002111222112110102
4313112231121211301220101
5223402214004341022001
62221440454222142145
7102164623422634043
oct6726553145615021
91156886074875412
10243453134314001
1170631992567a97
122337aa22121955
13a5ac6bbc15051
1444192a1c95a93
151d22b94a13e6b
hexdd6b59971a11

243453134314001 has 2 divisors, whose sum is σ = 243453134314002. Its totient is φ = 243453134314000.

The previous prime is 243453134313979. The next prime is 243453134314009. The reversal of 243453134314001 is 100413431354342.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 243096462585601 + 356671728400 = 15591551^2 + 597220^2 .

It is a cyclic number.

It is not a de Polignac number, because 243453134314001 - 210 = 243453134312977 is a prime.

It is a super-2 number, since 2×2434531343140012 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (243453134314009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121726567157000 + 121726567157001.

It is an arithmetic number, because the mean of its divisors is an integer number (121726567157001).

Almost surely, 2243453134314001 is an apocalyptic number.

It is an amenable number.

243453134314001 is a deficient number, since it is larger than the sum of its proper divisors (1).

243453134314001 is an equidigital number, since it uses as much as digits as its factorization.

243453134314001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 207360, while the sum is 38.

Adding to 243453134314001 its reverse (100413431354342), we get a palindrome (343866565668343).

The spelling of 243453134314001 in words is "two hundred forty-three trillion, four hundred fifty-three billion, one hundred thirty-four million, three hundred fourteen thousand, one".