Base | Representation |
---|---|
bin | 110111100000100101101100… |
… | …001101010110101100111111 |
3 | 1012000101210111102110122000111 |
4 | 313200211230031112230333 |
5 | 223444324420141342002 |
6 | 2223120414410010451 |
7 | 102264646551616642 |
oct | 6740455415265477 |
9 | 1160353442418014 |
10 | 244132051512127 |
11 | 70873904629589 |
12 | 2346a516116a27 |
13 | a62b72756869c |
14 | 44400a9171a59 |
15 | 1d3567cc653d7 |
hex | de096c356b3f |
244132051512127 has 2 divisors, whose sum is σ = 244132051512128. Its totient is φ = 244132051512126.
The previous prime is 244132051512073. The next prime is 244132051512133. The reversal of 244132051512127 is 721215150231442.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 244132051512127 - 215 = 244132051479359 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 244132051512127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (244132051512227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122066025756063 + 122066025756064.
It is an arithmetic number, because the mean of its divisors is an integer number (122066025756064).
Almost surely, 2244132051512127 is an apocalyptic number.
244132051512127 is a deficient number, since it is larger than the sum of its proper divisors (1).
244132051512127 is an equidigital number, since it uses as much as digits as its factorization.
244132051512127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 134400, while the sum is 40.
The spelling of 244132051512127 in words is "two hundred forty-four trillion, one hundred thirty-two billion, fifty-one million, five hundred twelve thousand, one hundred twenty-seven".
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