Base | Representation |
---|---|
bin | 1110001101100010101… |
… | …0010100101101101101 |
3 | 212100012110012200221121 |
4 | 3203120222110231231 |
5 | 13000011201022000 |
6 | 304055025100541 |
7 | 23432225315614 |
oct | 3433052245555 |
9 | 770173180847 |
10 | 244153142125 |
11 | 945aa0a1402 |
12 | 3b39a487751 |
13 | 1a03c952289 |
14 | bb620a887b |
15 | 653e881b1a |
hex | 38d8a94b6d |
244153142125 has 16 divisors (see below), whose sum is σ = 320740130880. Its totient is φ = 185042379600.
The previous prime is 244153142089. The next prime is 244153142131. The reversal of 244153142125 is 521241351442.
It is not a de Polignac number, because 244153142125 - 29 = 244153141613 is a prime.
It is a super-2 number, since 2×2441531421252 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51398287 + ... + 51403036.
It is an arithmetic number, because the mean of its divisors is an integer number (20046258180).
Almost surely, 2244153142125 is an apocalyptic number.
244153142125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
244153142125 is a deficient number, since it is larger than the sum of its proper divisors (76586988755).
244153142125 is a wasteful number, since it uses less digits than its factorization.
244153142125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102801357 (or 102801347 counting only the distinct ones).
The product of its digits is 38400, while the sum is 34.
Adding to 244153142125 its reverse (521241351442), we get a palindrome (765394493567).
The spelling of 244153142125 in words is "two hundred forty-four billion, one hundred fifty-three million, one hundred forty-two thousand, one hundred twenty-five".
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