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2442101204113 is a prime number
BaseRepresentation
bin100011100010011000100…
…100110010010010010001
322122110111020020222121221
4203202120210302102101
5310002410402012423
65105515200045041
7341302354510264
oct43423044622221
98573436228557
102442101204113
11861764511a4a
12335366903781
1314939b374bbc
14862ac300cdb
15437d0ab1e5d
hex23898932491

2442101204113 has 2 divisors, whose sum is σ = 2442101204114. Its totient is φ = 2442101204112.

The previous prime is 2442101204093. The next prime is 2442101204131. The reversal of 2442101204113 is 3114021012442.

Together with next prime (2442101204131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1321357147009 + 1120744057104 = 1149503^2 + 1058652^2 .

It is a cyclic number.

It is not a de Polignac number, because 2442101204113 - 221 = 2442099106961 is a prime.

It is a super-2 number, since 2×24421012041132 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2442101904113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1221050602056 + 1221050602057.

It is an arithmetic number, because the mean of its divisors is an integer number (1221050602057).

Almost surely, 22442101204113 is an apocalyptic number.

It is an amenable number.

2442101204113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2442101204113 is an equidigital number, since it uses as much as digits as its factorization.

2442101204113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 2442101204113 its reverse (3114021012442), we get a palindrome (5556122216555).

The spelling of 2442101204113 in words is "two trillion, four hundred forty-two billion, one hundred one million, two hundred four thousand, one hundred thirteen".