Base | Representation |
---|---|
bin | 100011100011010001011… |
… | …000110000000011010111 |
3 | 22122112221122202211201212 |
4 | 203203101120300003113 |
5 | 310011333403204201 |
6 | 5110153525212035 |
7 | 341335110230003 |
oct | 43432130600327 |
9 | 8575848684655 |
10 | 2443054350551 |
11 | 862103543a81 |
12 | 335591b6101b |
13 | 1494c0988b89 |
14 | 8635cb33703 |
15 | 438395daabb |
hex | 238d16300d7 |
2443054350551 has 2 divisors, whose sum is σ = 2443054350552. Its totient is φ = 2443054350550.
The previous prime is 2443054350493. The next prime is 2443054350593. The reversal of 2443054350551 is 1550534503442.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2443054350551 - 214 = 2443054334167 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2443054350499 and 2443054350508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2443054350151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1221527175275 + 1221527175276.
It is an arithmetic number, because the mean of its divisors is an integer number (1221527175276).
Almost surely, 22443054350551 is an apocalyptic number.
2443054350551 is a deficient number, since it is larger than the sum of its proper divisors (1).
2443054350551 is an equidigital number, since it uses as much as digits as its factorization.
2443054350551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720000, while the sum is 41.
Adding to 2443054350551 its reverse (1550534503442), we get a palindrome (3993588853993).
The spelling of 2443054350551 in words is "two trillion, four hundred forty-three billion, fifty-four million, three hundred fifty thousand, five hundred fifty-one".
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