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244341310139 is a prime number
BaseRepresentation
bin1110001110001111100…
…0001000001010111011
3212100200120021121221022
43203203320020022323
513000402333411024
6304125430133055
723440001603453
oct3434370101273
9770616247838
10244341310139
1194696332863
123b4314b118b
131a06c925bb4
14bb7d08ad63
15655115035e
hex38e3e082bb

244341310139 has 2 divisors, whose sum is σ = 244341310140. Its totient is φ = 244341310138.

The previous prime is 244341310117. The next prime is 244341310153. The reversal of 244341310139 is 931013143442.

244341310139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 244341310139 - 220 = 244340261563 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 244341310099 and 244341310108.

It is not a weakly prime, because it can be changed into another prime (244341310439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122170655069 + 122170655070.

It is an arithmetic number, because the mean of its divisors is an integer number (122170655070).

Almost surely, 2244341310139 is an apocalyptic number.

244341310139 is a deficient number, since it is larger than the sum of its proper divisors (1).

244341310139 is an equidigital number, since it uses as much as digits as its factorization.

244341310139 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 35.

The spelling of 244341310139 in words is "two hundred forty-four billion, three hundred forty-one million, three hundred ten thousand, one hundred thirty-nine".