Base | Representation |
---|---|
bin | 1110001110001111100… |
… | …0001000001011001001 |
3 | 212100200120021121221211 |
4 | 3203203320020023021 |
5 | 13000402333411103 |
6 | 304125430133121 |
7 | 23440001603503 |
oct | 3434370101311 |
9 | 770616247854 |
10 | 244341310153 |
11 | 94696332876 |
12 | 3b4314b11a1 |
13 | 1a06c925bc5 |
14 | bb7d08ad73 |
15 | 655115036d |
hex | 38e3e082c9 |
244341310153 has 2 divisors, whose sum is σ = 244341310154. Its totient is φ = 244341310152.
The previous prime is 244341310139. The next prime is 244341310223. The reversal of 244341310153 is 351013143442.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 221306266624 + 23035043529 = 470432^2 + 151773^2 .
It is a cyclic number.
It is not a de Polignac number, because 244341310153 - 237 = 106902356681 is a prime.
It is not a weakly prime, because it can be changed into another prime (244341370153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122170655076 + 122170655077.
It is an arithmetic number, because the mean of its divisors is an integer number (122170655077).
Almost surely, 2244341310153 is an apocalyptic number.
It is an amenable number.
244341310153 is a deficient number, since it is larger than the sum of its proper divisors (1).
244341310153 is an equidigital number, since it uses as much as digits as its factorization.
244341310153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 244341310153 its reverse (351013143442), we get a palindrome (595354453595).
The spelling of 244341310153 in words is "two hundred forty-four billion, three hundred forty-one million, three hundred ten thousand, one hundred fifty-three".
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