Base | Representation |
---|---|
bin | 110111101101110011100100… |
… | …101000100100010011110111 |
3 | 1012010121121212112001221010011 |
4 | 313231303210220210103313 |
5 | 224104220023330324002 |
6 | 2225053544145441051 |
7 | 102420402212521021 |
oct | 6755634450442367 |
9 | 1163547775057104 |
10 | 245040310011127 |
11 | 710940148a4964 |
12 | 23596554040187 |
13 | a696281c94897 |
14 | 447202b2b1011 |
15 | 1d4e0da2ee8d7 |
hex | dedce4a244f7 |
245040310011127 has 2 divisors, whose sum is σ = 245040310011128. Its totient is φ = 245040310011126.
The previous prime is 245040310011113. The next prime is 245040310011251. The reversal of 245040310011127 is 721110013040542.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 245040310011127 - 27 = 245040310010999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (245040310071127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122520155005563 + 122520155005564.
It is an arithmetic number, because the mean of its divisors is an integer number (122520155005564).
Almost surely, 2245040310011127 is an apocalyptic number.
245040310011127 is a deficient number, since it is larger than the sum of its proper divisors (1).
245040310011127 is an equidigital number, since it uses as much as digits as its factorization.
245040310011127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 31.
Adding to 245040310011127 its reverse (721110013040542), we get a palindrome (966150323051669).
The spelling of 245040310011127 in words is "two hundred forty-five trillion, forty billion, three hundred ten million, eleven thousand, one hundred twenty-seven".
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