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2451398149051 is a prime number
BaseRepresentation
bin100011101011000010101…
…101110100001110111011
322200100111011002201111221
4203223002231310032323
5310130430411232201
65114053505532511
7342051634315105
oct43530255641673
98610434081457
102451398149051
118656a5390315
12337120344137
1314a2204c3557
1486910d32575
1543b76d974a1
hex23ac2b743bb

2451398149051 has 2 divisors, whose sum is σ = 2451398149052. Its totient is φ = 2451398149050.

The previous prime is 2451398149049. The next prime is 2451398149063. The reversal of 2451398149051 is 1509418931542.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2451398149051 - 21 = 2451398149049 is a prime.

It is a super-4 number, since 4×24513981490514 (a number of 51 digits) contains 4444 as substring.

Together with 2451398149049, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 2451398149051.

It is not a weakly prime, because it can be changed into another prime (2451398144051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1225699074525 + 1225699074526.

It is an arithmetic number, because the mean of its divisors is an integer number (1225699074526).

Almost surely, 22451398149051 is an apocalyptic number.

2451398149051 is a deficient number, since it is larger than the sum of its proper divisors (1).

2451398149051 is an equidigital number, since it uses as much as digits as its factorization.

2451398149051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1555200, while the sum is 52.

The spelling of 2451398149051 in words is "two trillion, four hundred fifty-one billion, three hundred ninety-eight million, one hundred forty-nine thousand, fifty-one".