Base | Representation |
---|---|
bin | 1110010001001110000… |
… | …0111000010100111111 |
3 | 212102202021010210220211 |
4 | 3210103200320110333 |
5 | 13004021433203203 |
6 | 304341020053251 |
7 | 23465545026205 |
oct | 3442340702477 |
9 | 772667123824 |
10 | 245140522303 |
11 | 94a66485786 |
12 | 3b615094227 |
13 | 1a1693912c1 |
14 | bc1728d075 |
15 | 659b3bdc6d |
hex | 391383853f |
245140522303 has 2 divisors, whose sum is σ = 245140522304. Its totient is φ = 245140522302.
The previous prime is 245140522241. The next prime is 245140522321. The reversal of 245140522303 is 303225041542.
245140522303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 245140522303 - 233 = 236550587711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (245140522703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122570261151 + 122570261152.
It is an arithmetic number, because the mean of its divisors is an integer number (122570261152).
Almost surely, 2245140522303 is an apocalyptic number.
245140522303 is a deficient number, since it is larger than the sum of its proper divisors (1).
245140522303 is an equidigital number, since it uses as much as digits as its factorization.
245140522303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 245140522303 its reverse (303225041542), we get a palindrome (548365563845).
The spelling of 245140522303 in words is "two hundred forty-five billion, one hundred forty million, five hundred twenty-two thousand, three hundred three".
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