Base | Representation |
---|---|
bin | 1110010001100011101… |
… | …0011100101111011011 |
3 | 212102222120121012102121 |
4 | 3210120322130233123 |
5 | 13004213131024011 |
6 | 304354013442111 |
7 | 23501025023446 |
oct | 3443072345733 |
9 | 772876535377 |
10 | 245231111131 |
11 | 95002629486 |
12 | 3b63b4a0337 |
13 | 1a18208b266 |
14 | bc2531065d |
15 | 65a4314e71 |
hex | 3918e9cbdb |
245231111131 has 2 divisors, whose sum is σ = 245231111132. Its totient is φ = 245231111130.
The previous prime is 245231111117. The next prime is 245231111159. The reversal of 245231111131 is 131111132542.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 245231111131 - 237 = 107792157659 is a prime.
It is a super-2 number, since 2×2452311111312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 245231111096 and 245231111105.
It is not a weakly prime, because it can be changed into another prime (245231121131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122615555565 + 122615555566.
It is an arithmetic number, because the mean of its divisors is an integer number (122615555566).
Almost surely, 2245231111131 is an apocalyptic number.
245231111131 is a deficient number, since it is larger than the sum of its proper divisors (1).
245231111131 is an equidigital number, since it uses as much as digits as its factorization.
245231111131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 720, while the sum is 25.
Adding to 245231111131 its reverse (131111132542), we get a palindrome (376342243673).
The spelling of 245231111131 in words is "two hundred forty-five billion, two hundred thirty-one million, one hundred eleven thousand, one hundred thirty-one".
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