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247106131 is a prime number
BaseRepresentation
bin11101011101010…
…00101001010011
3122012222021212221
432232220221103
51001224344011
640304201511
76060240016
oct1656505123
9565867787
10247106131
11117537548
126a909297
133c26b45c
1424b6537d
1516a61971
hexeba8a53

247106131 has 2 divisors, whose sum is σ = 247106132. Its totient is φ = 247106130.

The previous prime is 247106113. The next prime is 247106137. The reversal of 247106131 is 131601742.

Together with previous prime (247106113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 247106131 - 27 = 247106003 is a prime.

It is a super-2 number, since 2×2471061312 = 122122879955578322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 247106096 and 247106105.

It is not a weakly prime, because it can be changed into another prime (247106137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 123553065 + 123553066.

It is an arithmetic number, because the mean of its divisors is an integer number (123553066).

Almost surely, 2247106131 is an apocalyptic number.

247106131 is a deficient number, since it is larger than the sum of its proper divisors (1).

247106131 is an equidigital number, since it uses as much as digits as its factorization.

247106131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

The square root of 247106131 is about 15719.6097597873. The cubic root of 247106131 is about 627.5203876912.

Adding to 247106131 its reverse (131601742), we get a palindrome (378707873).

The spelling of 247106131 in words is "two hundred forty-seven million, one hundred six thousand, one hundred thirty-one".