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248113 = 475279
BaseRepresentation
bin111100100100110001
3110121100101
4330210301
530414423
65152401
72052235
oct744461
9417311
10248113
1115a458
12bb701
1388c18
14665c5
154d7ad
hex3c931

248113 has 4 divisors (see below), whose sum is σ = 253440. Its totient is φ = 242788.

The previous prime is 248099. The next prime is 248117. The reversal of 248113 is 311842.

248113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311842 = 2155921.

It is a cyclic number.

It is not a de Polignac number, because 248113 - 29 = 247601 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (248117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2593 + ... + 2686.

It is an arithmetic number, because the mean of its divisors is an integer number (63360).

2248113 is an apocalyptic number.

It is an amenable number.

248113 is a deficient number, since it is larger than the sum of its proper divisors (5327).

248113 is an equidigital number, since it uses as much as digits as its factorization.

248113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5326.

The product of its digits is 192, while the sum is 19.

The square root of 248113 is about 498.1094257289. The cubic root of 248113 is about 62.8371539648.

Adding to 248113 its reverse (311842), we get a palindrome (559955).

It can be divided in two parts, 248 and 113, that added together give a square (361 = 192).

The spelling of 248113 in words is "two hundred forty-eight thousand, one hundred thirteen".

Divisors: 1 47 5279 248113