Base | Representation |
---|---|
bin | 1110011100011010110… |
… | …1010000110110100111 |
3 | 212201111210011010022011 |
4 | 3213012231100312213 |
5 | 13031201100441101 |
6 | 305555213015051 |
7 | 23633211523066 |
oct | 3470655206647 |
9 | 781453133264 |
10 | 248146890151 |
11 | 962694a5406 |
12 | 40113a84487 |
13 | 1a5281950a4 |
14 | c0206721dd |
15 | 66c52be751 |
hex | 39c6b50da7 |
248146890151 has 2 divisors, whose sum is σ = 248146890152. Its totient is φ = 248146890150.
The previous prime is 248146890139. The next prime is 248146890157. The reversal of 248146890151 is 151098641842.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 248146890151 - 25 = 248146890119 is a prime.
It is a super-3 number, since 3×2481468901513 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 248146890095 and 248146890104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (248146890157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 124073445075 + 124073445076.
It is an arithmetic number, because the mean of its divisors is an integer number (124073445076).
Almost surely, 2248146890151 is an apocalyptic number.
248146890151 is a deficient number, since it is larger than the sum of its proper divisors (1).
248146890151 is an equidigital number, since it uses as much as digits as its factorization.
248146890151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 552960, while the sum is 49.
The spelling of 248146890151 in words is "two hundred forty-eight billion, one hundred forty-six million, eight hundred ninety thousand, one hundred fifty-one".
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