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24879343110113 is a prime number
BaseRepresentation
bin1011010100000101011000…
…11010001000011111100001
310021002102221012100120001102
411222002230122020133201
511230110343314010423
6124525225030444145
75145321213110552
oct552025432103741
9107072835316042
1024879343110113
117a222a7645378
122959949803655
1310b615c0668ab
14620249346329
152d227eae7c28
hex16a0ac6887e1

24879343110113 has 2 divisors, whose sum is σ = 24879343110114. Its totient is φ = 24879343110112.

The previous prime is 24879343110071. The next prime is 24879343110143. The reversal of 24879343110113 is 31101134397842.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23915347070224 + 963996039889 = 4890332^2 + 981833^2 .

It is a cyclic number.

It is not a de Polignac number, because 24879343110113 - 220 = 24879342061537 is a prime.

It is a super-4 number, since 4×248793431101134 (a number of 55 digits) contains 4444 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (24879343110143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12439671555056 + 12439671555057.

It is an arithmetic number, because the mean of its divisors is an integer number (12439671555057).

Almost surely, 224879343110113 is an apocalyptic number.

It is an amenable number.

24879343110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

24879343110113 is an equidigital number, since it uses as much as digits as its factorization.

24879343110113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 435456, while the sum is 47.

The spelling of 24879343110113 in words is "twenty-four trillion, eight hundred seventy-nine billion, three hundred forty-three million, one hundred ten thousand, one hundred thirteen".