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2491207783 is a prime number
BaseRepresentation
bin1001010001111100…
…1101000001100111
320102121122110121221
42110133031001213
520100222122113
61051111121211
7115506626311
oct22437150147
96377573557
102491207783
111069249309
12596373207
1330917155c
14198c027b1
15e8a9098d
hex947cd067

2491207783 has 2 divisors, whose sum is σ = 2491207784. Its totient is φ = 2491207782.

The previous prime is 2491207687. The next prime is 2491207837. The reversal of 2491207783 is 3877021942.

2491207783 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (2491207837) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2491207783 - 217 = 2491076711 is a prime.

It is a super-2 number, since 2×24912077832 = 12412232436159550178, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2491277783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1245603891 + 1245603892.

It is an arithmetic number, because the mean of its divisors is an integer number (1245603892).

Almost surely, 22491207783 is an apocalyptic number.

2491207783 is a deficient number, since it is larger than the sum of its proper divisors (1).

2491207783 is an equidigital number, since it uses as much as digits as its factorization.

2491207783 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 169344, while the sum is 43.

The square root of 2491207783 is about 49912.0003906876. Note that the first 3 decimals coincide. The cubic root of 2491207783 is about 1355.6158895496.

The spelling of 2491207783 in words is "two billion, four hundred ninety-one million, two hundred seven thousand, seven hundred eighty-three".