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249436433 is a prime number
BaseRepresentation
bin11101101111000…
…01100100010001
3122101100200110102
432313201210101
51002323431213
640430142145
76116113631
oct1667414421
9571320412
10249436433
11118889314
126b651955
133c8a602c
14251b06c1
1516d72158
hexede1911

249436433 has 2 divisors, whose sum is σ = 249436434. Its totient is φ = 249436432.

The previous prime is 249436423. The next prime is 249436457. The reversal of 249436433 is 334634942.

249436433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 161976529 + 87459904 = 12727^2 + 9352^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-249436433 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (249436423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 124718216 + 124718217.

It is an arithmetic number, because the mean of its divisors is an integer number (124718217).

Almost surely, 2249436433 is an apocalyptic number.

It is an amenable number.

249436433 is a deficient number, since it is larger than the sum of its proper divisors (1).

249436433 is an equidigital number, since it uses as much as digits as its factorization.

249436433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 186624, while the sum is 38.

The square root of 249436433 is about 15793.5566925250. The cubic root of 249436433 is about 629.4868021853.

The spelling of 249436433 in words is "two hundred forty-nine million, four hundred thirty-six thousand, four hundred thirty-three".