25001043481 has 2 divisors, whose sum is σ = 25001043482. Its totient is φ = 25001043480.

The previous prime is 25001043479. The next prime is 25001043497. The reversal of 25001043481 is 18434010052.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18356185225 + 6644858256 = 135485^2 + 81516^2 .

It is a cyclic number.

It is not a de Polignac number, because 25001043481 - 2¹ = 25001043479 is a prime.

It is a super-2 number, since 2×25001043481² (a number of 22 digits) contains 22 as substring.

Together with 25001043479, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (25001053481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12500521740 + 12500521741.

It is an arithmetic number, because the mean of its divisors is an integer number (12500521741).

Almost surely, 2^25001043481 is an apocalyptic number.

It is an amenable number.

25001043481 is a deficient number, since it is larger than the sum of its proper divisors (1).

25001043481 is an equidigital number, since it uses as much as digits as its factorization.

25001043481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 28.

The spelling of 25001043481 in words is "twenty-five billion, one million, forty-three thousand, four hundred eighty-one".